Question

How many atoms are present in 0.35 mol of carbon dioxide?

Answer 1

0.35 moles carbon dioxide (6.022 X 10^23/1 mole CO2) = 2.1 X 10^23 atoms of
carbon dioxide

Answer 2

Answer : The number of atoms present are, $6.3\times 10^{23}$

Explanation : Given,

Moles of $CO_2$ = 0.35 mole

As we know that, 1 mole of substance contains $6.022\times 10^{23}$ number of atoms.

In $CO_2$, there 1 atom of carbon and 2 atoms of oxygen. So, the total number of atoms in $CO_2$ are, 3.

As, 1 mole of $CO_2$ contains $3\times 6.022\times 10^{23}$ number of atoms.

So, 0.35 mole of $CO_2$ contains $0.35\times 3\times 6.022\times 10^{23}=6.3\times 10^{23}$ number of atoms.

Therefore, the number of atoms present are, $6.3\times 10^{23}$