[tex] 2\frac{3}{8} [/tex] ÷ [tex] 1\frac{1}{4} [/tex] equals [tex] 1\frac{9}{10} [/tex].
First, convert [tex]2 \frac{3}{8} [/tex] to improper fraction. Use this rule: [tex]a \frac{b}{c} [/tex] = [tex] \frac{ac+b}{c} [/tex]. Your problem should look like: [tex] \frac{2x8+3}{8} [/tex] ÷ [tex] 1\frac{1}{4} [/tex].
Second, simplify 2 x 8 to get 16. Your problem should look like: [tex] \frac{16+3}{8} [/tex] ÷ [tex]1 \frac{1}{4} [/tex].
Third, simplify 16 + 3 to get 19. Your problem should look like: [tex] \frac{19}{8} [/tex] ÷ [tex]1 \frac{1}{4} [/tex].
Fourth, convert [tex] 1\frac{1}{4} [/tex] to improper fraction. Use the same rule as earlier. Your problem should look like: [tex] \frac{19}{8} [/tex] ÷ [tex] \frac{4+1}{4} [/tex].
Fifth, simplify 4 + 1 to get 5. Your problem should look like: [tex] \frac{19}{8} [/tex] ÷ [tex] \frac{5}{4} [/tex].
Sixth, apply this rule: a ÷ [tex] \frac{b}{c} [/tex] = a × [tex] \frac{c}{b} [/tex]. Your problem should look like: [tex] \frac{19}{8} [/tex] × [tex] \frac{4}{5} [/tex].
Seventh, apply this rule: [tex] \frac{a}{b} [/tex] × [tex] \frac{c}{d} [/tex] = [tex] \frac{ac}{bd} [/tex]. Your problem should look like: [tex] \frac{19x4}{8x5} [/tex].
Eighth, simplify 19 × 4 to get 76. Your problem should look like: [tex] \frac{76}{8x5} [/tex].
Ninth, simplify 8 × 5 to get 40. Your problem should look like: [tex] \frac{76}{40} [/tex].
Tenth, simplify. Your problem should look like: [tex] \frac{19}{10} [/tex].
Eleventh, convert to mixed fraction. Your problem should look like: [tex]1 \frac{9}{10} [/tex] which is the answer.
Answer as mixed number form: [tex] 1\frac{9}{10} [/tex].
Answer as exact form: [tex] \frac{19}{10} [/tex].
Answer as decimal form: 1.9.
