Question

Intercepts of 9x^2+9y=81

Answer 1

$x=0\\ \\ 9x^2+9y=81\\ \\ 9.0^2+9y=81\\ \\ 9y=81\\ \\ y=\frac{81}{9}\\ \\ \boxed{y=9}$

$y=0\\ \\ 9x^2+9.0=81\\ \\ 9x^2=81\\ \\ x^2=\frac{81}{9}\\ \\ x^2=9\\ \\ \boxed{x= \pm 3}$