Relationship A has a lesser rate than Relationship B. This table represents Relationship B.

Hours worked 2 4 5 8
Amount paid ($) 36.50 73 91.25 146
Which equation could represent Relationship A?

Hours worked is represented by x and Amount paid is represented by y.

Select each correct answer.

y = 18.1x

y = 18.6x

y = 18.3x

y = 18x

Respuesta :

Answer:

y = 18.1x ; and y = 18x

Explanation:

The rate of change in Relationship B can be found by using the formula for slope:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Using the first two points, we have

[tex]m=\frac{73-36.50}{4-2}=\frac{36.50}{2}=18.25[/tex]

We know that Relationship A has a lesser rate than this.  The choices given for Relationship A are written in slope-intercept form, y=mx+b, where m is the slope and b is the y-intercept (in this case b = 0).

The slope of the first equation is 18.1; this is less than 18.25.

The slope of the second equation is 18.6; this is greater than 18.25.

The slope of the third equation is 18.3; this is greater than 18.25.

The slope of the fourth equation is 18; this is less than 18.25.

Answer:

Option A and D.

Step-by-step explanation:

If a linear function passes through two points, then the rate of change is

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

From the given table it is clear that the Relationship B have two ordered pairs (2,36.50) and (4,73). So, the rate of Relationship B is

[tex]m=\dfrac{73-36.50}{4-2}[/tex]

[tex]m=\dfrac{36.50}{2}[/tex]

[tex]m=18.25[/tex]

The rate of relation B is 18.25.

Let hours worked is represented by x and amount paid is represented by y. So the Relationship B is defined as

[tex]y=kx[/tex]

Where, k is the rate of relationship A.

It is given that Relationship A has a lesser rate than Relationship B.

[tex]k<18.25[/tex]

We know that

[tex]18.1<18.25[/tex], [tex]18.6>18.25[/tex], [tex]18.3>18.25[/tex] and [tex]18<18.25[/tex].

The relationship A could be

[tex]y=18.1x[/tex] and [tex]y=18x[/tex]

Therefore, the correct options are A and D.