The value of x for 1st figure is 16 units, for 2nd figure is 22, for 3rd figure is 5, for 4th figure is 6.25, and for 5th figure is 26.67. The value of AE and DE is 20 units and 8 units, respectively.
The given triangles in the figure are similar.
For similar triangles, the ratio of their sides is equal.
Now, solve for the value of x for all the triangles one by one,
For first figure,
[tex]\dfrac{x}{4}=\dfrac{20}{5}\\\dfrac{x}{4}=4\\x=16[/tex]
For 2nd figure,
[tex]\dfrac{x-10}{36}=\dfrac{5}{15}\\x-10=12\\x=22[/tex]
For the 3rd figure,
[tex]\dfrac{AE}{DE}=\dfrac{AB}{CD}\\\dfrac{2x+10}{x+3}=\dfrac{10}{4}\\4x+20=5x+15\\x=5[/tex]
So, the value of AE and DE will be,
[tex]AE=2x+10\\=2\times 5+10\\=20\\DE=x+3\\=8[/tex]
For the 4th figure,
[tex]\dfrac{x}{5}=\dfrac{5}{4}\\x=\dfrac{25}{4}\\x=6.25[/tex]
For the 5th figure,
[tex]\dfrac{x}{30}=\dfrac{40}{45}\\x=\dfrac{80}{3}\\x=26.67[/tex]
Therefore, value of x for 1st figure is 16 units, for 2nd figure is 22, for 3rd figure is 5, for 4th figure is 6.25, and for 5th figure is 26.67. The value of AE and DE is 20 units and 8 units, respectively.
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https://brainly.com/question/19738610