The components of vector are ax and ay (both positive), and the angle that it makes with respect to the positive x axis is θ. Find the angle θ if the components of the displacement vector are (a) ax = 12 m and ay = 12 m, (b) ax = 20 m and ay = 12 m, and (c) ax = 12 m and ay = 20 m.

Respuesta :

we can use formula

[tex]\theta=tan^{-1}(\frac{a_y}{a_x})[/tex]

(a)

we are given

[tex]a_x=12,a_y=12[/tex]

now, we can plug values

[tex]\theta=tan^{-1}(\frac{12}{12})[/tex]

[tex]\theta=tan^{-1}(1)[/tex]

[tex]\theta=\frac{\pi}{4}rad [/tex]

(b)

we are given

[tex]a_x=20,a_y=12[/tex]

now, we can plug values

[tex]\theta=tan^{-1}(\frac{12}{20})[/tex]

[tex]\theta=tan^{-1}(\frac{3}{5})[/tex]

[tex]\theta=30.96^{\circ \:} [/tex]

(c)

we are given

[tex]a_x=12,a_y=20[/tex]

now, we can plug values

[tex]\theta=tan^{-1}(\frac{20}{12})[/tex]

[tex]\theta=tan^{-1}(\frac{5}{3})[/tex]

[tex]\theta=59.03^{\circ \:} [/tex]


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