Question

what are the roots to this quadratic equation?

Answer 1

16x^2=9
x^2=9/18
x=sqrt(9/16)
x=3/4,-3/4
so the root of the quadratic equation are 3/4 and -3/4 

Answer 2

Answer:

$\frac34$ and $-\frac34$

Step-by-step explanation:

Hello!

We have to solve for x to find the roots of the quadratic.

Solve for x

• $16x^2 = 9$
• $x^2 = \frac{9}{16}$
• $\sqrt{x^2} = \sqrt{\frac{9}{16}}$
• $x = \pm\frac{\sqrt9}{\sqrt{16}}$
• $x = \pm\frac34$

The roots of the quadratic are $\frac34$ and $-\frac34$.

The roots of the quadratic is when the value of y is 0, or when the graph intersects the x-axis.