On your first attempt you leave the surface of the earth at v = 5534 m/s. how far from the center of the earth will you get?

Question

27-09-2017
Physics

contestada

On your first attempt you leave the surface of the earth at v = 5534 m/s. how far from the center of the earth will you get?

Respuesta :

Otras preguntas

3. Prepare a T account for each transaction. Label the account title for each account affected. Use the chart of accounts you created in Question 1. Write the d

100CPOINTS WILL GIVE BRAINLYEST

Applying a Limited Quantity Hazmat label to a package that was not prompted by the VAS system is as serious of a violation as not applying a Limited Quantity Ha

Quest Which of the following has kinetic energy? OA. Light OB. Gravity C. Food OD. Motion

In order to search for a lost ring, 27 students spread out in a line across the schoolyard, 2.5 m between each pair of students. The people at either end of the

2. Which of the following 242, 492, 772, 131² or 1892 end with digit 1?

arunner jack 12km north then turns and runs 16km in 3hours calculate his average velocity

On Wednesday, they pick a total of 89 kg of strawberries. The mean mass of each strawberry is 22 g. Work out the number of strawberries they picked. Give your

Jamie owns a pizza shop in town, and she’s working on paying off equipment expenses. The remaining balance of $6,550 is financed and requires a monthly payment

Question 19 Simplify 2x+3 10x³+15x²

ACCESS MORE EDU ACCESS

Kalahira Kalahira · Answer 1 · 2017-10-07T16:45:59+02:00

It's another energy balance equation, though: energy to start with is the same as energy that you end with. Suppose that we start a distance r0 from the Earth and end a distance r1 from the Moon, then the energy balance gives: 1 v02 - G M / r0 - G m / (D - r0) = 1 v12 - G M / (D - r1) - G m / r1 ...where m is the moon's mass. One simple limit takes D ? ? and 1 v02 ? G M / r0 (the escape velocity equation), to yield: 1 v12 ? G M / r1 v1 ? ?( 2 G M / r1 ) = 2377 m/s.