In a population of humans, the frequency of straight hair is 34 percent. If straight hair is the recessive phenotype, what is the frequency of the homozygous recessive genotype? 17 percent 34 percent 66 percent 68 percent

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34 percent  fam  I saw it on quizlet  fyi thats where I get my answers and help on my work


Answer:

Option B, 34 percent

Explanation:

Given,

Frequency of straight hair [tex]= 34[/tex]%

Let the allele for straight hair be represented by "s" and the allele for any other hair type be represented by "S"

Here, S is dominant over s.

Thus, as per the Hardy Weinberg's equation

the frequency of a homozygous recessive genotype is represented by "[tex]q^{2}[/tex]" while the frequency of homozygous dominant genotype is represented by [tex]p^{2}[/tex]

[tex]q^{2} =[/tex] [tex]34[/tex]%

Since straight hair is a recessive trait. thus this phenotype is only expressed when the genotype of recessive allele is homozygous.

Therefore , frequency of the homozygous recessive genotype is equal to the frequency of straight hair in normal human population i.e [tex]34[/tex]%

hence, option B is correct

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