Jake bought a scooter for RS 3,00,000and sold it to Sophia after Two years deduction 20% of the price. Sophia sold it to Eron in Rs 6000 profit.
A》Find the selling price for Jake.
B》Compar the price of Jake and Eron of the scooter in ratio from.

[The ans of B should be 50:41]​

Respuesta :

A) Selling Price for Jake: Jake sold the scooter to Sophia after deducting 20% from the purchase price of RS 3,00,000.

The deduction amount is: [ 20% \ 3,00,000 = frac{20}{100} times 3,00,000 = 60,000 ]

So, the selling price for Jake is: [ 3,00,000 - 60,000 = 2,40,000 ]

B) Price Comparison in Ratio: Sophia sold the scooter to Eron at a profit of RS 6,000. Therefore, Eron’s purchase price is: [ 2,40,000 + 6,000 = 2,46,000 ]

Now, we compare the prices of Jake and Eron in the form of a ratio: [ frac{Jake’s Selling Price}{{Eron’s Purchase Price}} = \frac{2,40,000}{2,46,000} ]

To simplify this ratio, we can divide both numbers by the greatest common divisor of both, which is 6,000: [ frac{2,40,000}{6,000} : frac{2,46,000}{6,000} = 40 : 41 ]

The simplified ratio of the price comparison between Jake and Eron is 40:41.

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