Respuesta :

 Assuming you want to know the value of "[tex]v[/tex]" 

So, step one we would have solve from the same value 

[tex] \frac{1}{12}(12-v) = \frac{1}{6}(v-6)\\ \frac{1}{12}(12) + \frac{1}{12} (-v) = \frac{1}{6}(v)+ \frac{1}{6} (-6) \\ 1 + \frac{-1}{12}(v) = \frac{1}{6}v + -01 \\ \frac{-1}{12} (v) +1 = \frac{1}{6} - 1 [/tex]

Step two we have to subtract by [tex] \frac{1}{6}v[/tex] on each of your sides (so it can kind of be easier for you to solve) 


So,[tex] \frac{1}{6} v + 1 - \frac{1}{6}v = \frac{1}{6}v - 1 \frac{1}{6}v [/tex] 
You would have to cancel out the right side because it would give you a(n) answer of 1 

Now that we got those steps out of your way, let's subtract 1 to your sides that we're working with 

[tex] \frac{-1}{4}(v) +1 -1 \\ = -1 -1 [/tex]

Finally we're close to our answer for [tex]v[/tex]

[tex] \frac{-1}{4}(v)= 2 [/tex]

[tex] \frac{4}{1} ( \frac{-1}{4} )[/tex] cancel this out because it gives you one 

But, keep: [tex] \frac{4}{1} (-2)[/tex] because it gives you the answer

[tex]v = 8 [/tex]

Good luck on your assignment
and enjoy your day

~[tex]MeIsKaitlyn:)[/tex]
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