Assuming you want to know the value of "[tex]v[/tex]"
So, step one we would have solve from the same value
[tex] \frac{1}{12}(12-v) = \frac{1}{6}(v-6)\\ \frac{1}{12}(12) + \frac{1}{12} (-v) = \frac{1}{6}(v)+ \frac{1}{6} (-6) \\ 1 + \frac{-1}{12}(v) = \frac{1}{6}v + -01 \\ \frac{-1}{12} (v) +1 = \frac{1}{6} - 1 [/tex]
Step two we have to subtract by [tex] \frac{1}{6}v[/tex] on each of your sides (so it can kind of be easier for you to solve)
So,[tex] \frac{1}{6} v + 1 - \frac{1}{6}v = \frac{1}{6}v - 1 \frac{1}{6}v [/tex]
You would have to cancel out the right side because it would give you a(n) answer of 1
Now that we got those steps out of your way, let's subtract 1 to your sides that we're working with
[tex] \frac{-1}{4}(v) +1 -1 \\ = -1 -1 [/tex]
Finally we're close to our answer for [tex]v[/tex]
[tex] \frac{-1}{4}(v)= 2 [/tex]
[tex] \frac{4}{1} ( \frac{-1}{4} )[/tex] cancel this out because it gives you one
But, keep: [tex] \frac{4}{1} (-2)[/tex] because it gives you the answer
[tex]v = 8 [/tex]
Good luck on your assignment
and enjoy your day
~[tex]MeIsKaitlyn:)[/tex]