Answer:
Parallel, since [tex]\vec u = 2\cdot \vec v[/tex].
Step-by-step explanation:
The relation between both vectors is determined by the use of the dot product, whose expression is:
[tex]\cos \theta = \frac{\vec u \bullet \vec v}{\|\vec u\| \|\vec v\|}[/tex]
Where:
[tex]\cos \theta = 1[/tex] if vectors are parallel to each other and [tex]\cos \theta = 0[/tex] if vectors are orthogonal. Then, norms and dot product are calculated hereafter:
[tex]\|\vec u\| = \sqrt{18^{2}+8^{2}}[/tex]
[tex]\|\vec u\| \approx 19.698[/tex]
[tex]\|\vec v \| = \sqrt{9^{2}+4^{2}}[/tex]
[tex]\|\vec v\| \approx 9.849[/tex]
[tex]\vec u \bullet \vec v = (18)\cdot (9) + (8)\cdot (4)[/tex]
[tex]\vec u \bullet \vec v = 194[/tex]
[tex]\cos \theta = \frac{194}{(19.698)\cdot (9.849)}[/tex]
[tex]\cos \theta = 1[/tex]
The two vectors are parallel to each other, which is also supported by the fact that one vector is multiply of the other one. That is,
[tex]18i + 8j = 2\cdot (9i + 4j)[/tex]
[tex]\vec u = 2\cdot \vec v[/tex]