Let the length of the side opposite the wall be x, and the lengths of the other 2 sides be y.
x+2y=240 ft
then
2y=240-x
y=(240-x)/2=120-x/2
The area of the rectangular enclosure is determined by the function
[tex]A(x)=x \cdot y =x \cdot (120-x/2)[/tex] (square feet)
both width and length must be >0,
so we must have:
i) x>0
ii) 120-x/2>0 (at the same time)
solving the second inequation:
120-x/2>0
120>x/2
240>x
so x must be smaller than 240, but also larger than 0.
Thus the domain is (0, 240)
Answer: Domain: (0, 240)