Respuesta :
Answer:
Explanation:
A) The genotype of the F1 offspring can be determined by understanding the alleles involved and their mode of transmission. In this case, the body color is controlled by a recessive allele, ebony (e), which produces a shiny black body. The wing length is normally long, but it is reduced in flies homozygous for the recessive allele, vestigial wing (v), which results in dwarfed wings.
When flies with normal phenotypes (reddish brown body and long wings) are crossed with black, vestigial-winged flies, we can assume that the black, vestigial-winged flies are homozygous for the recessive alleles ebony (ee) and vestigial wing (vv).
Therefore, the genotype of the F1 offspring will be:
Heterozygous for body color (Ee)
Heterozygous for wing length (Vv)
B) To determine the phenotypic and genotypic ratios of the F2 generation, we need to cross the F1 offspring, which are heterozygous for both traits.
If we cross two heterozygous F1 flies (EeVv), the F2 generation will have the following genotypes and phenotypes:
Genotypes:
1/4 will be homozygous dominant (EEVV) with a reddish brown body and long wings
1/4 will be homozygous recessive (eevv) with a shiny black body and vestigial wings
1/2 will be heterozygous (EeVv) with a reddish brown body and long wings
Phenotypes:
3/4 will have a reddish brown body and long wings
1/4 will have a shiny black body and vestigial wings
The genotypic and phenotypic ratios of the F2 generation are as follows:
Genotypic: 1:2:1 for EEVV:EeVv:eevv
Phenotypic: 3:1 for reddish brown body and long wings : shiny black body and vestigial wings
I hope this helps clarify the genotypes and phenotypes of the F1 and F2 offspring in this Drosophila fly cross.