Respuesta :
Solve the first for y
y=13x-90 and the second is y=x^2-x-42
When there is/are solutions y=y so we can say:
x^2-x-42=13x-90 subtract 13x from both sides
x^2-14x-42=-90 add 90 to both sides
x^2-14x+48=0 expand so that it is easy to factor...
x^2-6x-8x+48=0 now factor 1st and 2nd pair of terms
x(x-6)-8(x-6)=0
(x-8)(x-6)=0
So there are two solutions, when x=6 and 8.
Using either original equation we can find the corresponding values for y. I'll use y=13x-90 because it is easier...
y(6)=-12, y(8)=14 so the two solutions are the points:
(6,-12) and (8,14)
y=13x-90 and the second is y=x^2-x-42
When there is/are solutions y=y so we can say:
x^2-x-42=13x-90 subtract 13x from both sides
x^2-14x-42=-90 add 90 to both sides
x^2-14x+48=0 expand so that it is easy to factor...
x^2-6x-8x+48=0 now factor 1st and 2nd pair of terms
x(x-6)-8(x-6)=0
(x-8)(x-6)=0
So there are two solutions, when x=6 and 8.
Using either original equation we can find the corresponding values for y. I'll use y=13x-90 because it is easier...
y(6)=-12, y(8)=14 so the two solutions are the points:
(6,-12) and (8,14)
The two solution points are : (6,-12) and (8,14)
What is system of equations ?
In mathematics, a system of equations, also known as a set of simultaneous or an equation system, is a finite set of equations for which we sought the common solutions.
The given is two equation 13x - y = 90
and the second is y = x² - x -42
Solve the first equation for y
y = 13x-90
Putting the value of y in second equation
x² - x -42 =13x - 90
x²- 14x- 42= -90
x²- 14x+48=0
x²-6x-8x+48=0
x(x-6)-8(x-6)=0
(x-8)(x-6)=0
x=6 and 8.
To find the corresponding values for y.
y=13x-90
y(6)=-12, y(8)=14
Therefore the two solutions are the points:
(6,-12) and (8,14)
To know more about system of equations
https://brainly.com/question/12895249
#SPJ2