1. Use the leading term to determine the end behavior of the graph of the function. a. A. f(x) = – 0.3x4 – 5x2 – 3x + 4
b. g(x) = 15x 7 + 4x3 – 3

Respuesta :

Step-by-step explanation:

the term with the highest exponent determines the behavior of the graph for very, very large positive values of x or very, very low negative values of x (= the end behavior).

a.

f(x) = -0.3x⁴ - 5x² - 3x + 4

the highest exponent is 4. that is even, making x⁴ always a positive number. as the square or the square of squares or ... of negative numbers always delivers positive numbers too.

the factor of -0.3 then turns this always positive number into an always negative number.

as mentioned, the larger the absolute value of x, the more x⁴ drowns out the other terms with lower exponents.

so, the end behavior for f(x) when x going to -infinity and to +infinity is going to -infinity in both cases.

b.

g(x) = 15x⁷ + 4x³ - 3

the highest exponent is 7. that is an uneven (odd) number, making this a positive number for positive x values, and a negative number for negative x values.

the factor 15 keeps the sign of the x⁷ term.

similar to a., the larger the absolute value of x, the more x⁷ drowns out the other terms with lower exponents.

so, the end behavior for g(x) when x is going to +infinity is going to +infinity. and when x is going to -infinity, it is going to -infinity.

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