Question

Solve the quadratic equation by completing the square. x^2-12x+22=0
Show what the form is and the solution.

FORM:
Solution:

Answer 1

$x^2-12x+22=0 \\ x^2-12x+36-14=0\\ (x-6)^2=14\\ x-6=-\sqrt{14} \vee x-6=\sqrt{14}\\ x=6-\sqrt{14} \vee x=6+\sqrt{14}$