Question

The function f is defined by f(x) x2 +3x-10.

If fx +5)x2 +kx+30, k = [?]

Find the smallest zero of f(x+5). x = [?]

Answer 1

f(x+5)=(x+5)²+3(x+5)-10
f(x)=x²+10x+25+3x+15-10
f(x)=x²+13x+30
k=13

x²+13x+30=0
(x+3)(x+10)=0
x=-3 or -10
the smallest zeros is x=-10

Answer 2

Answer:

K=13

X=-10

Step-by-step explanation: