Question

What is the value of b2 - 4ac for the following equation?

5x2 + 7x = 6

Answer 1

5x^2 + 7x - 6 = 0

Call "a" 5, "b" 7 and "c" -6

Rule is x1,2 = (-b±√b^2-4ac)/2a

Substituting the value to b^2-4ac...

(-6)^2-4*5*(-6)

36+120 <- answer