Question

A fantasy board game makes use of four dice. The first is a standard 6-faced die, the second die has 4 faces, and the other two have 10 faces each. If all the dice are thrown together and their combination dictates a certain outcome of the game, how many possible outcomes exist?

Answer 1

6 x 4 x 10 x 10 = 2400 possible outcomes

Answer 2

Answer:

2400

Step-by-step explanation:

Given : The first is a standard 6-faced die, the second die has 4 faces, and the other two have 10 faces each.

To Find: If all the dice are thrown together and their combination dictates a certain outcome of the game, how many possible outcomes exist?

Solution:

No. of faces of first die = 6

No. of faces of second die = 4

No. of faces of third die = 10

No. of faces of fourth die = 10

Now we are supposed to find the the number of possible outcomes exist.

So, Number of possible outcomes if all the dice are thrown together :

= $6 \times 4 \times 10 \times 10$

=$2400$

Hence there are 2400 possible outcomes if all the dice are thrown together and their combination dictates a certain outcome of the game.