Answer:
Explanation:
3.86 L CO x 1 mol O2 x 1mole O2 x 22.4 L O2 = 1.93 L O2
22.4 L CO 2 mole CO 1 mole O2
The volume of oxygen, O₂ in litre (L) required to burn 3.86 L of carbon monoxide , CO is 1.93 L
2CO + O₂ —> 2CO₂
From the balanced equation above,
2 L of CO requires 1 L of O₂
From the balanced equation above,
2 L of CO requires 1 L of O₂
Therefore,
3.86 L of CO will require = 3.86 / 2 = 1.93 L of O₂
Thus, 1.93 L of O₂ is needed for the reaction
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