Respuesta :

p=1
p^4+p^2+p-k=0

1+1+1-k=0 k=3

The value of k is 3 if p - 1 is a factor of [tex]p^4+p^2+p-k[/tex]

How to determine the value of k?

The expression is given as:

[tex]p^4+p^2+p-k[/tex]

The factor is given as:

p - 1

Set the factor to 0

p - 1 = 0

Add  to both sides

p = 1

Substitute 1 for p in the expression and equate it to 0

[tex]1^4+1^2+1-k = 0[/tex]

Evaluate the exponents

1+1+1-k = 0

Evaluate the sum

3-k = 0

Add k to both sides

k = 3

Hence, the value of k is 3 if p - 1 is a factor of [tex]p^4+p^2+p-k[/tex]

Read more about factors at:

https://brainly.com/question/723406

#SPJ2

ACCESS MORE