Question

Max observes the zoo and the library from a helicopter flying at a height of 100 times square root of 3 feet above the ground, as shown below:

*image below*

What is the distance between the zoo and the library?

Answer 1

Answer:

Hence, the distance between zoo and library is:

200 feet.

Step-by-step explanation:

Let H denote the position of Helicopter.

Z denote the position of Zoo.

and L denote the position of library.

Hence, we will firstly find the distance between G and zoo and then we find the distance between G and library and subtract the first distance from second to obtain the distance between zoo and library.

In ΔHGZ.

tan 60°=HG/GZ

⇒ √3=100√3/GZ

Hence, GZ=100 feet.

Similarly in ΔHGL

tan 30°=HG/GL

⇒ 1/√3=100√3/GL

⇒ GL=300 feet.

Hence, the distance between zoo and library is:

GL-GZ

=300-100

=200 feet.

Hence, the distance between zoo and library is 200 feet.

Answer 2

In this exercise we want to use the knowledge of triangles to calculate the distance value, so we find that:

200 feet.

Initially we have to organize the information given in the exercise, then we have that:

• Let H denote the position of Helicopter.

• Z denote the position of Zoo.

• L denote the position of library.

We know that it is a triangle, so we can write the equations as:

• $tan 60=HG/GZ\\\sqrt{3} =100\sqrt{3} /GZ\\GZ=100$

• $tan 30=HG/GL\\1/\sqrt{3} =100\sqrt{3} /GL\\GL=300$

Then calculating the distance we find that:

$GL-GZ=300-100=200$

See more about distance at brainly.com/question/989117