Question

Two friends, Bob and Ben, each buy one lottery ticket. Each ticket contains six numbers from a total of one hundred numbers (0–99). Bob chooses the numbers 1, 2, 3, 4, 5, 6, and Ben chooses the numbers 39, 45, 66, 72, 74, 89. Who has a higher probability of winning?

Answer 1

Ben has the higher probability of winning. I don't know the mathematical explanation but its kinda just really obvious that when they do the lottery balls (what are those called idk) there is a very very very little chance of them calling out those numbers in order. just because, you know, THERE'S A LOT OF FLIPPING NUMBER COMBINATIONS WHY GO WITH A FUDGING SEQUENCE WHAT THE FRUIT BOB 

Answer 2

Answer: Both has equal probability of winning.

Step-by-step explanation:

It is given that Bob and Ben, each buy one lottery ticket.

Each ticket contains six numbers from a total of one hundred numbers (0–99).

Since, both the friends have bought same number of ticket with 6 numbers on each ticket.

Probability for choosing any numbers from (0-99) is same for all numbers from 0 to 99 i.e. $\frac{1}{100}$.

Therefore, The probability of winning would be equal for both the friends.