Answer:
Image distance = 3.33cm; image height = 1.33cm
Explanation:
The question is incomplete, according to the data given in the question, we can get the distance of image from the mirror and the image height.
First we must know that the focal length (f) of a converging mirror is negative and the image distance from the mirror (v) is negative since it produce virtual images only.
Using the mirror formula to get the image distance;
1/f = 1/u+1/v where;
f is the focal length
u is the object distance
v is the image distance
Given u = 10cm, f = -5cm(for converging mirror)
v = ?
1/v = 1/f-1/u
1/v = -1/5 - 1/10
1/v = -2-1/10
1/v = -3/10
-3v = 10
v = 10/-3
v = -3.33cm
This means the image is 3.33cm behind the mirror.
To get the image height, we will use the magnification formula
Magnification = image height(H1)/object height (H2) = Image distance (v)/Object distance (u)
Since M = H1/H2 = v/u
Therefore, H1/H2 = v/u... (1)
Given H1= 4cm(object 4cm tall)
H2 = ? v = 3.33cm u = 10cm
Substituting in eqn 1 to get H2, we have;
H2/4=3.33/10
10H2 = 3.33×4
10H2= 13.32
H2 = 13.32/10
H2 = 1.33cm
The image height will be 1.33cm
