Question

A particular compound contains, by mass, 25.5 % carbon, 40.4 % fluorine, and 34.1 % oxygen. a 0.050-mol sample of this compound weighs 9.40 g. the molecular formula of this compound is:

Answer 1

CxFyOz
m=nM
M=m/n

M=9.40/0.050=188 g/mol

w(C)=0.255
w(F)=0.404
w(O)=0.341

w(C)=xM(C)/M
w(F)=yM(F)/M
w(O)=yM(O)/M

12x/188=0.255   x=4
19y/188=0.404   y=4
16z/188=0.341   z=4

C₄F₄O₄

Answer 2

The molecular formula of compound will be $C_{4}F_{4} O_{4}$.

What is molecular formula?

The molecular formula would be an equation that specifies how many atoms within each element there are in a single compound's molecule.

What is compound?

A compound represents a substance created by the chemical fusion of more than one elements.

Let the molecular formula of the given compound will be $C_{x}F_{y} O_{z}$.

Molecular mass can be determined by the formula:

M = m/n

M = 9.40/0.050

M = 188 g/mol

Given data:

Mass of carbon = 25.5 %

Mass of fluorine = 34.1 %

Mass of oxygen = 34.1 %

Mol of the sample = 0.050-mol

Weight of the compound = 9.40 g

Calculation of molecular formula:

Weight of carbon = x M (C) / M

12x/188 = 0.255

x =  0.255

Weight of Florine = y M (C) / M

19 y / 188 = 0.404

y = 0.404

Weight of oxygen = z M (C) / M

16 z / 188 = 0.341

z = 0.341

The molecular formula of compound will be $C_{4}F_{4} O_{4}$.

To know more about mole and molecular formula.

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