Question

(3a3 − 5b3) + a3 + b3 = (a3 + b3).

Answer 1

3a^3-5b^3+xa^3+yb^3=1a^3+1b^3

3z-5v+xz+yv=z+v
3z+xz+yv-5v=1z+v

3z+xz=1z

3+x=1

x=-2

yv-5v=1v

y-5=1

y=6


(3a^3-5b^3)+ -2 a^3 +6 b^3=(a^3+b^3)

Answer 2

3a^3-5b^3+xa^3+yb^3=1a^3+1b^3
replace a^3 with z
replace b^3 with v (to make it easier to see)
3z-5v+xz+yv=z+v
3z+xz+yv-5v=1z+v

the terms match them
3z+xz=1z
divide both sides by z
3+x=1
minus 3
x=-2

yv-5v=1v
dividie both sides by v
y-5=1
addd 5 to both sides
y=6



(3a^3-5b^3)+ -2 a^3 +6 b^3=(a^3+b^3)