Question

The circle below is centered at the point (8, 4) and has a radius of length 4. What is its equation?

Answer 1

(x-8)^2 + (y-4)^2= 16

Answer 2

Answer:

$(x-8)^{2}+(y-4)^{2}=16$

Step-by-step explanation:

we know that

The equation of a circle into center radius form is equal to

$(x-h)^{2}+(y-k)^{2}=r^{2}$

where

(h,k) is the radius of the circle

r is the radius of the circle

In this problem we have

$r=4\ units$

$(h,k)=(8,4)$

substitute

$(x-8)^{2}+(y-4)^{2}=4^{2}$

$(x-8)^{2}+(y-4)^{2}=16$