Respuesta :
As air pressure in an area decreases the density of the gas particles in that area decreases
Answer:
If pressure decreases density decreases and increase the pressure if the pressure increases.
Explanation:
From the ideal gas law we have
[tex]pv=nRT\\\Rightarrow pv=n\frac{R}{molar\ mass\ of\ gas}T\\\Rightarrow pv=mR_sT[/tex]
Now divide both sides by volume we get
[tex]p=\frac{m}{v}R_sT\\\Rightarrow p=\rho R_sT[/tex]
Where,
R = Gas constant
[tex]R_s[/tex] = Mass-specific gas constant
T = Temperature of gas
n = Number of moles of gas
m = Mass of gas
v = Volume of gas
p = Pressure of gas
ρ = Density of gas
It can be seen from the equation that the pressure and density are proportionally related.
If pressure decreases density decreases and increase the preusure if the pressure increases.
