A circle is centered at (−4, 9) and has a radius of 11.

What is the equation of the circle?

Enter the equation in the box using lower case variables x and y.

Respuesta :

(x+4)^2+(y-9)^2=121 are your three answers because your equation for a circle is (x+h)^2+(y+k)^2=r^2, where h and k are your numbers for the center of a circle r= the radius of the circle. i hope this helps.

If a circle has a center at (−4, 9) and has a radius of 11. Then the equation of the circle is x² + y² + 8x - 18y = 24.

What is the equation of the circle with radius r units, centered at (x,y)?

If a circle O has a radius of r units length and it has got its center positioned at (h, k) point of the coordinate plane, then, its equation is given as:

[tex](x-h)^2 + (y-k)^2 = r^2[/tex]

A circle is centered at (−4, 9) and has a radius of 11.

Then we have

[tex]\begin{aligned} \rm (x+4)^2 + (y-9)^2 = 11^2\\\\\rm x^2 + 8x + 16 + y^2 - 18y + 81 = 121\\\\\rm x^2 + y^2 + 8x - 18y = 24 \end{aligned}[/tex]

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