Answer:
- Four consecutive even integers are 14, 16, 18 and 20
- Third number in the sequence is 18
Step-by-step explanation:
Let N be the first even integer
Each consecutive integer is 2 away from the previous integer
Next consecutive integer = N + 2, next one = N+4 and the last one = N +6
Add these expressions together, set them equal to 68 to solve for N
==> N + (N +2) + (N +4) + (N + 6) = 68
==> N + N +2 + N +4 + N + 6 = 68
==> 4N + 12 = 68
==> 4N = 68-12
==> 4N = 56
N = 56/4 = 14
So the integers are 14, 16, 18 and 20
Third integer in the sequence is 18
