Four students wrote sequences during math class.

Andre - 3/4, 3/8, - 3/16, - 3/32..
Brenda 3/5, -3 /8, 3/16, 3/32..
Camille 3/4, 3/8, - 3/16, - 3/32..
Doug 3/4, - 3/8, 3/16, -3 /32..

Which student wrote a geometric sequence?
Andrea
Brenda
Camille
Doug

Respuesta :

Doug because his sequence follows a rule of multiplying by -1/2 Hope I got it right for your sake.

Answer:

Doug wrote geometric sequence.

Step-by-step explanation:

a geometric sequence is where we get common ratio between consecutive terms

[tex]\text{common ratio}=\frac{a_2}{a_1}[/tex]

In case of Andre:

On substituting the values so as to find common ratio is

[tex]\frac{\frac{3}{8}}{\frac{3}{4}}=\frac{-1}{2}[/tex]

[tex]\frac{\frac{-3}{16}}{\frac{3}{8}}=\frac{-1}{2}[/tex]

[tex]\frac{\frac{-3}{32}}{\frac{-3}{16}}=\frac{1}{2}[/tex]

Andre did not write a geometric sequence.

In case of Brenda:

On substituting the values so as to find common ratio is

[tex]\frac{\frac{-3}{8}}{\frac{3}{5}}=\frac{-5}{8}[/tex]

[tex]\frac{\frac{3}{16}}{\frac{-3}{8}}=\frac{-1}{2}[/tex]

[tex]\frac{\frac{3}{32}}{\frac{3}{16}}=\frac{1}{2}[/tex]

Brenda did not write a geometric sequence.

In case of Camille

On substituting the values so as to find common ratio is

[tex]\frac{\frac{3}{8}}{\frac{3}{4}}=\frac{1}{2}[/tex]

[tex]\frac{\frac{-3}{16}}{\frac{3}{8}}=\frac{-1}{2}[/tex]

[tex]\frac{\frac{-3}{32}}{\frac{-3}{16}}=2[/tex]

Camille did not write a geometric sequence.

In case of Doug:

On substituting the values so as to find common ratio is

[tex]\frac{\frac{-3}{8}}{\frac{3}{4}}=\frac{-1}{2}[/tex]

[tex]\frac{\frac{3}{16}}{\frac{-3}{8}}=\frac{-1}{2}[/tex]

[tex]\frac{\frac{-3}{32}}{\frac{3}{16}}=\frac{-1}{2}[/tex]

Doug wrote a geometric sequence.

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