assuming you're not suppose to use a calculator to solve this,
[tex]\frac{4.8 \times 10^8}{1.2 \times 10^4} \times (2.2 \times 10^{-6})[/tex]
now, start by only looking at and multiplying/dividing the "10s"
[tex]\frac{10^8}{10^4} \times 10^{-6}[/tex]
[tex]10^4 \times 10^{-6}
[/tex]
[tex]10^{-2}[/tex]
so when you multiply/divide the 10s, you get 10^-2
now look at the other numbers (4.8, 1.2,2.2)
[tex]\frac{4.8}{1.2} \times 2.2[/tex]
[tex]4 \times 2.2[/tex]
[tex]8.8[/tex]
multiply the two answers
[tex]8.8 \times 10^{-2}[/tex]
if you're asking why you can solve it this way, its because you multiplication is commutative/associative (you can multiply numbers in any order and group them however you want and still get the same answer)