The distance between the x-intercept and the y-intercept of Line k is 13 units.
Linear equation
Linear equation is in the form:
y = mx + b
Where y, x are variables, m is the rate of change and b is the y intercept.
Line k crosses the x-axis at 5, that is (5, 0). Line k is parallel to line 5y-12x = 5.
The slope of line 5y-12x = 5 is:
- 5y = 12x + 5
- y = (12/5)x + 1
Line k has a slope of 12/5 which is the same as slope of line 5y-12x = 5.
[tex]y-y_1=m(x-x_1)\\\\y-0=\frac{12}{5}(x-5) \\\\y=\frac{12}{5}x-12 [/tex]
y intercept of line k is:
y = 12/5(0) - 12
y = -12
y intercept = (0, -12)
Distance between y and x intercept:
[tex]Distance=\sqrt{(-12-0)^2+(5-0)^2}=13 [/tex]
The distance between the x-intercept and the y-intercept of Line k is 13 units.
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