Question

In the triangle below, angle B measures 60° and BC is 18. What is the length of AC

Answer 1

Answer:

$AC=9\sqrt{3}\ units$

Step-by-step explanation:

see the attached figure to better understand the problem

In the right triangle ABC

$sin(60\°)=\frac{AC}{BC}$

$sin(60\°)=\frac{\sqrt{3}}{2}$

so

$\frac{AC}{BC}=\frac{\sqrt{3}}{2}$

we have

$BC=18\ units$

substitute

$\frac{AC}{18}=\frac{\sqrt{3}}{2}$

$AC=18\frac{\sqrt{3}}{2}=9\sqrt{3}\ units$

Answer 2

The above answer is correct! The answer is D, or $9\sqrt{3}$.

Just got it right on edge 2020, hope this helps!! :) Good luck!