Answer:
[tex]17.796\frac{\text{g}}{\text{mol}}[/tex]
Step-by-step explanation:
We are asked to find the mass of 0.12 mole of Magnesium Nitrate [tex]\text{Mg(NO3)}2[/tex].
We know that molar mass of Magnesium Nitrate is [tex]183.4\frac{\text{g}}{\text{mol}}[/tex].
To find mass of 0.12 mol of Magnesium Nitrate, we will multiply [tex]183.4\frac{\text{g}}{\text{mol}}[/tex] by 0.12
[tex]0.12\times 183.4\frac{\text{g}}{\text{mol}}[/tex]
[tex]17.796\frac{\text{g}}{\text{mol}}[/tex]
Therefore, the mass of 0.12 mol of Magnesium Nitrate is [tex]17.796\frac{\text{g}}{\text{mol}}[/tex].
