Respuesta :
General equation of a circle with centre (h, k) is given by:
[tex](x - h)^{2} + (y - k)^{2} = r^{2}[/tex]
Now, the origin is the centre and radius is 20, so substituting these points in yields:
[tex]x^{2} + y^{2} = 20^{2}[/tex]
[tex]x^{2} + y^{2} = 400[/tex]
[tex](x - h)^{2} + (y - k)^{2} = r^{2}[/tex]
Now, the origin is the centre and radius is 20, so substituting these points in yields:
[tex]x^{2} + y^{2} = 20^{2}[/tex]
[tex]x^{2} + y^{2} = 400[/tex]
Answer:
Required equation of circle is x² + y² = 400
Step-by-step explanation:
We are given center of the circle i origin and radius = 20 units.
We have to find the equation of the circle.
We know that coordinates of the origin is ( 0 , 0 )
To write the equation of circle we use standard equation of circle,
Standard equation of circle is given as below,
( x - h )² + ( y - k )² = r²
here, ( h , k ) is coordinate of the center of the circle. and r is radius of the circle.
Using given information and standard equation of circle, we have
( x - 0 )² + ( y - 0 )² = 20²
x² + y² = 400
Therefore, Required equation of circle is x² + y² = 400