Question

The length of a rectangle is 2 more than 3 times the width. If the perimeter is 100, find the length and width of the rectangle.

If l = length and w = width, which of the following systems could be used to solve the problem?

l = 3w + 2 and 2l + 2w = 100
l = 2w + 3 and 2l + 2w = 100
l + 2 = 3w and 2l + 2w = 100

Answer 1

W=width of rectangle
3w+3=length of rectangle
2(l+w)=100
l=3w+3
2(3w+3+w)=100
2(2w+3)=100
8w+6=100
8w=94
w=47/4 (the width of the rectangle)
3w+3=3(47/4+3)=177/4 (this is the length of the rectangle)
Have a nice day

Answer 2

Answer:

the answer is the first one