Question

A student ran the following reaction in the laboratory at 546 K:

COCl2 (g) CO (g) + Cl2 (g)

When she introduced 0.723 moles of COCl2 (g) into a 1.00 liter container, she found the equilibrium concentration of Cl2 (g) to be 3.38×10-2 M.

Calculate the equilibrium constant, Kc, she obtained for this reaction.

Kc =

Answer 1

Answer:  For the reaction 2HCl(g) ==> H2(g) + Cl2(g), the Keq = [H2(g)][Cl2(g)]/[HCl(g)]^2

Explanation: