Respuesta :

h(x) = 11/x-4       Sorry this is so late.

Using the domain concept, it is found that [tex]f(x) = \frac{1}{x - 3}[/tex] has the same domain as [tex](m \times n)(x) = \frac{x^2 + 4x - 5}{x - 3}[/tex]

------------------------

  • The domain of a function is given by all possible values of the input.
  • The functions are:

[tex]m(x) = \frac{x + 5}{x - 1}[/tex]

[tex]n(x) = x - 3[/tex]

  • Their multiplication is given by:

[tex](m \times n)(x) = \frac{x + 5}{x - 1} \times x - 3 = \frac{(x + 5)(x - 1)}{x - 3} = \frac{x^2 + 4x - 5}{x - 3}[/tex]

  • In a fraction, the denominator cannot be 0, thus, the domain is all real numbers except 3. A function with the same domain is one in which the numerator is changed while the denominator is the same, for example, [tex]f(x) = \frac{1}{x - 3}[/tex]

A similar problem is given at https://brainly.com/question/10891721

ACCESS MORE
EDU ACCESS