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19-06-2015
Mathematics

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Jay traveled from Miami to Jacksonville, a distance of 320 miles. He left Miami at 8:00am, stopped for lunch for 30 minutes, and stopped for two 15 minute breaks at rest areas. He arrived in Jacksonville at 2:15pm. What was his average rate of speed during his travel time? Please explain the steps to get the answer. Thanks!

Respuesta :

20-06-2015

To find the “Average Rate of Speed", we know we need the Total Distance and the Total Time. The Total Distance is 320 miles and the Total Time is 14:15 - 8:00 = 6:15 hours = 6.25 hours .So the Average Rate = 320 miles/ 6.25 hours = 51.20 mph.

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