Thirty randomly selected students took the calculus final. If the sample mean was 95 and the standard deviation was 6.6, construct a 99% confidence interval for the mean score of all students. You may use your calculator to solve.

Respuesta :

Given:

Sample mean = 95

Standard deviation = 6.6

The confidence interval is the range of values that you expect your estimate to fall between a certain percentage of the time if you run your experiment again or re-sample the population in the same way.

We have to construct a 99% confidence interval for the mean score of all the students.

Sample Standard Error =

[tex]\frac{Standard Deviation}{\sqrt{n} } \\= \frac{6.6}{\sqrt{30} }[/tex]

= 1.205

t-value for the 99% confidence interval = 2.756

(use the t-tables for this)

Margin of error = 2.756 x 1.205 = 3.321

If you are asked to report the confidence interval, you should include the upper and lower bounds of the confidence interval.

So, for the 99% confidence interval:

(95 - 3.321, 95 + 3.321) = (91.679, 98.321)

This is the final confidence interval.

To learn more about confidence intervals,

brainly.com/question/24131141

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