Given:
Sample mean = 95
Standard deviation = 6.6
The confidence interval is the range of values that you expect your estimate to fall between a certain percentage of the time if you run your experiment again or re-sample the population in the same way.
We have to construct a 99% confidence interval for the mean score of all the students.
Sample Standard Error =
[tex]\frac{Standard Deviation}{\sqrt{n} } \\= \frac{6.6}{\sqrt{30} }[/tex]
= 1.205
t-value for the 99% confidence interval = 2.756
(use the t-tables for this)
Margin of error = 2.756 x 1.205 = 3.321
If you are asked to report the confidence interval, you should include the upper and lower bounds of the confidence interval.
So, for the 99% confidence interval:
(95 - 3.321, 95 + 3.321) = (91.679, 98.321)
This is the final confidence interval.
To learn more about confidence intervals,
brainly.com/question/24131141
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