Question

5. If there is 7.7 moles of gaseous nitric acid at a pressure of 0.09 atm and
at a temperature of 56 OC, what is the volume of the container that the
w
gas is in?

Answer 1

Answer: Thus the volume of the container that the gas is in 2311 L

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 0.09 atm

V = Volume of gas = Volume of container = ?

n = number of moles = 7.7

R = gas constant =$0.0821Latm/Kmol$

T =temperature =$56^0C=(56+273)K=329K$

$V=\frac{nRT}{P}$

$V=\frac{7.7mol\times 0.0821Latm/K mol\times 329K}{0.09atm}=2311L$

Thus the volume of the container that the gas is in 2311 L