Respuesta :
We can use the same equation to figure out with only substituting the amount he was paid per photo.
Site A y = $0.85x = $0.85(5) = $4.25
Site B y = $0.40x = $0.40(5) = $2.00
We can see that Jim was paid $2.25 more at site A than Site B.
Site A y = $0.85x = $0.85(5) = $4.25
Site B y = $0.40x = $0.40(5) = $2.00
We can see that Jim was paid $2.25 more at site A than Site B.
Determine how much more Jim paid at site A than at site B
Jim paid $2.25 more at site A than at site B
Given:
Site A:
y = 0.85x
Site B:
y = 0.40x
where,
y = total amount paid
x = number of photos
If Jim provides 5 photos for each site
Site A:
y = 0.8x
y = 0.85(5)
y = $4.25
Site B:
y = 0.40x
y = 0.40(5)
y = $2
Site A - site B
= $4.25 - $2
= $2.25
Therefore, Jim paid $2.25 more at site A than at site B
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