Question

He John Hancock Building in Chicago i 455 meter tall, which i about 1,400 feet, or about a quarter of a mile high. It ha one of the fatet elevator in the world, traveling at 20. 5 mile per hour, or about 5 meter per econd. How many econd woud it take to travel the the length of the building?

Answer 1

The required number of seconds would it take to travel the the length of the building is 91.

What is speed and its formula?

The equation for speed is basic like distance partitioned by time. You take the distance voyaged (for instance 3 meters) and gap it when (three seconds) to get the speed (one meter each second) Thus, we can characterize Speed as the pace of progress of position of an article toward any path.

According to question:

We have,

length of the building = 455 meter

speed of elevator = 5 m/s

We know,

speed = distance/time

5 = 455/time

Time = 455/5

Time = 91 seconds.

Thus,time take to travel the the length of the building is 91 seconds.

To know more about speed visit:

brainly.com/question/2004627

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