The slope of a line perpendicular to the given equation of line is 6.
For the stated question, the equation of the line is given as;
3x + 18y = 10
This can be written as;
y = -3/18 x + 10/18
y = -1/6 x + 5/9
Comparing with general equation of line in slope intercept form.
y = mx + c
slope m = -1/6
The relation of slope for the two perpendicular lines are-
m x m1 = -1
m1 = -1/(-1/6)
m1 = 6
Thus, the slope of a line perpendicular to the given equation of line is 6.
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