Question

assume that a rubber-tired tractor has a total weight of 25,000 lb on its driving wheels. the maximum rimpull in low gear is 9,000 lb. if the tractor is operating in wet sand, with a coefficient of traction of 0.30, what is the maximum possible rimpull prior to slippage of the tires? (see example 6.5 in the textbook for reference)

Answer 1

The maximum possible rim pulls prior to tire slippage is 7,500 lb.

The friction between a drive wheel and the road surface is what is referred to as vehicle traction. The percentage of the total engine power that can be propelled forward by the friction between the tire and the track is known as the coefficient of traction.

This is given by the formula, usable traction or usable force = (coefficient of traction x normal force/weight on powered running gear).

Here, the coefficient of traction is 0.30 and the weight on the powered running gear is 25,000 lb. The maximum possible rimpull prior to slippage of the tires is given by,

Usable force=0.30×25,000 lb = 7,500 lb.

The answer is 7,500 lb.

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