The particle's acceleration is 3.7*10-9 m/s2, according to the formula. A point mass of 8.25 kg and a point mass of 13.5 kg are kept in site at a distance of 50.0 cm.
Here, the mass m is pulled toward the two particles by gravity. the force generated by the initial mass moving in a -X direction and the second mass moving in a +X direction.
The following is the expression for Newton's law of gravitation:
F =GMm/r^2
The gravitational constant G, the masses M and m, the gravitational force F, and the separation between the mass center's r are all present in this situation. the force acting against the first mass is negative, When we substitute F=GM1m/r1, we obtain,
F1 = -(6.67x10^-11 Nm'/kg)(8.25kg)m/(0.2m)*(0.2m)=-1.37x10^-8 m
F2 also equals 1*10^-8.
F2 = F1+F2
ma = F1+F2
acceleration = F1+F2/m
acceleration = -1.3*10^-8 +1*10^-8m/m
a = -3.7*10^-9 m/s^2
Learn more about acceleration here
https://brainly.com/question/12550364
#SPJ4