The correct value of the product of a and b is 224
Taking the prime factorization of 161 reveals that it is equal to 23*7. Therefore, the only ways to represent 161 as a product of two positive integers are 161*1 and 23*7. Because neither 161 nor 1 is a two-digit number, the only two-digit factor of 161 is 23, we know that a and b are 23 and 7. Because 23 is a two-digit number, we know that a, with its two digits reversed, gives 23.
Therefore, a = 32 and b = 7. Multiplying our two correct values of a and b yields.
The correct product must have been
a*b =32*7
=224
Learn more about multiplying positive integers here: https://brainly.com/question/11453536
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