Question

Calculus help please!!! Click the link to see the integral.

$\int\limits { \frac{cosx}{ \sqrt{sinx} } } \, dx$

Answer 1

noice

ook, so use u subsitution

remember that dy/dx(sin(x))=cos(x)

u=sin(x)
du/dx=cos(x)
du=cos(x) dx
so then

$\int\limits{ \frac{cos(x)}{ \sqrt{sin(x)} } } \, dx$
replace
$\int\limits{ \frac{1}{ \sqrt{u} } } \, du$
we do some stuff
$\int\limits{ u^ \frac{-1}{2} } } \, du$
$\frac{u^ \frac{1}{2} }{ \frac{1}{2} }$
$2 \sqrt{u}$
u=sin(x)
$2 \sqrt{sin(x)}$